Hi David.
Your answer brought me closer. Knowing datatypes is important.
If i do as you suggested:
<xsl:variable name="xmlString" select="/*[local-name()='Invoice']" />
and:
<xsl:variable name="pdfBytes">
<xsl:value-of select="transf:rtrtransform($xmlString)"/>
</xsl:variable>
then it sends a NodeSet (I THINK) to the java method.
But the java method does not get called. I get an error:
javax.xml.transform.TransformerException: java.lang.
NoSuchMethodException: For extension function, could not find method dk.
edbgruppen.genericdocumentprocess.transformation.TransformManagerImpl.
rtrtransform([ExpressionContext,] #NODESET).
Checked both static and instance methods.
Is one of my datatypes wrong?
public static String rtrtransform(NodeSet object2Transform) {
try {
//method is simplified.
System.out.println("OK " + "");
return "ok";
} catch (Exception ex) {
System.out.println("Error " + "");
return "Error";
}
}
I know i didnt send complete files, but i think you understand the
problem.
Best regards,
Richard Trans
----Oprindelig meddelelse----
Fra: davidc(_at_)nag(_dot_)co(_dot_)uk
Dato: 06/12/2007 17:53
Til: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Emne: Re: [xsl] Calling java from xsl - with xml as parameter
<xsl:variable name="xmlString">
<xsl:copy-of select="/*[local-name()='Invoice']" />
</xsl:variable>
There is no need to copy it, just
<xsl:variable name="xmlString" select="/*[local-name()='Invoice']" />
f select="transf:rtrtransform(string($xmlString))"/>
^^^^^^
the string function will throw away all the tree structure and just
make
a string of the element contents. If you don't want that, just pass
the
xml to your extension functrion, assuming your function can accept XML
nodes (using some object model)
David
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