Re: [xsl] xalan and replace "regex"

Hello,
I haven't participated here in the last couple years because these great
folks have answered so many of my questions that I can pretty much
accomplish what I need to on my own now.  :-)

It looks like you're trying to use the exslt extension functions.  To
use them you have to include the particular namespace of the function
you're wanting to use, e.g. str:replace(string, replace1, replace2).

Mansour wrote:
> Hello:
> Is there any way I can use replace with xalan. I have tried every
> thing possible but couldn't get it to work:
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <xsl:stylesheet version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:xalan="http://xml.apache.org/xalan";
> xmlns:str="http://exslt.org/strings";>
>    <xsl:import href="str/str.xsl" />
>      <xsl:template match="program">
>        <xsl:value-of select="replace(.,'public','&lt;KeyWord&gt; pulic
> &lt;/KeyWord&gt;')" />
>    </xsl:template>
> </xsl:stylesheet>
>
>
>
>
> I need to scan a piece of java code and be able to highlight the words
> based on their meaning. Anyone had luck with xalan regex ??  or
> analyze-string ??
>
>
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