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[xsl] RE: first n nodes from a current-group

2008-02-07 07:21:20
Thank you very much Michael. It's working.

Regards,
Manish

-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com] 
Sent: Thursday, February 07, 2008 7:06 PM
To: Manish_Jaiswal; xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: first n nodes from a current-group


But I wanted only the first two name elements having highest counts.
that is output like:


Try
 
<School>
  <xsl:for-each-group select=" School/student 
                      group-by="name/tokenize(., ';\s*')"> 
    <xsl:sort data-type="number" select="count(current-group())"
order="descending" />
    <xsl:sort select="current-grouping-key()"/> 
    <xsl:if test="position() <= 2">
      <name count="{count(current-group())}"> 
        <xsl:value-of select="current-grouping-key()"/> 
      </name> 
    </xsl:if> 
  </xsl:for-each-group> 
</School>

Michael Kay
http://www.saxonica.com/





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