Can't see a problem with your code, other than the inversion of "test" and
"if". Perhaps it's a namespace issue.
However, <xsl:if test="parent::some-tag"> is better.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Mansour [mailto:mansour77(_at_)yahoo(_dot_)com]
Sent: 16 February 2008 07:35
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How to test the parent name
I am trying to test the name of the parent.
<xsl:test if="name(parent::*)='some-tag'">direct descendant</xsl:test>
If I do this:
<xsl:value-of select="name(parent::*)" /> Then I get the name
of the parent output correctly, but when putting it in a test
element, it does not.
Why ? What do I do to perform the test ?
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