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Re: [xsl] using str:tokenize named template results

2008-03-28 15:36:31
I tried that, but it didn't work either. My output was:

token: A City
city: A City
city: A City
city: A City
token: B City
token: C City

There are <city> elements in the xml for both B City and C City. I did try all the options you suggested, but couldn't get them to work.


On Fri, 28 Mar 2008 22:29:53 +0000 (GMT)
 David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:

as I said, I think you want

      <xsl:for-each select="$root//city[. = current()]">
not
      <xsl:for-each select="$root//city[. = $ns/token]">

otherwise the inner loop doesn't depend on teh outer loop at all so
you'll get the same inner loop repeated each iteration of the outer
loop.

David


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