Hi Michael,
Thank you so much for the quick response.
Michael >>However, it's not clear to me that you need to create an RTF in
the first place. Why not define $filter as
<xsl:variable name="filter" select="//RecursoEx1[($option=1 and
F_FIN=$date1 and contains(TITULO,'o')) or ($option=2 and F_FIN=$date2)]"/>
I want to count the RecursoEx1 elements:
<p>Number: <xsl:value-of
select="count(exsl:node-set($filter)/RecursoEx1)"/></p> CORRECT!
I want to iterate over the RecursoEx1 elements:
<xsl:for-each select="exsl:node-set($filter)/RecursoEx1"> CORRECT !
I use xsl:copy-of and exsl:node-set because to error "Cannot process a
result tree fragment as a node-set under XSLT 1.0" if i code :
<xsl:variable name="filtro">
<xsl:choose>
<xsl:when test="$option=1">
<xsl:copy-of
select="//RecursoEx1[F_FIN=$date1]"/></xsl:when>
<xsl:otherwise>
<xsl:copy-of
select="//RecursoEx1[F_FIN=$date2]"/></xsl:otherwise>
</xsl:choose>
</xsl:variable>
<p>Number: <xsl:value-of select="$filter"/></p>
<xsl:for-each select="$filter">
<p><xsl:value-of select="TITULO"/></p>
</xsl:for-each>
and i don´t know if exits another posibility. Exists??
The variable "option" is to received from one formulary, but there are more
and then the "filter" will be dynamic.
How can i do to construct the filter dynamic? For example, i receive one
varible named "title" from the formulary with the value: "John Martin Car
Monday" and i like to enumerate the RecursoEx1 elements that meet with this
condition: TITLE=John or TITLE=Martin or TITLE=Car or TITLE=Monday.
or title variable is Apple Pencil, ..... then the condition will be
TITLE=Apple or TITLE=Pencil
i don´t know how may parameters i will receive in advance..
Thanks again Michael,
Alexander
----- Mensaje original -----
De: "Michael Kay" <mike(_at_)saxonica(_dot_)com>
Para: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Enviado: sábado, 12 de abril de 2008 14:03
Asunto: RE: [xsl] Cannot process a result tree fragment as a node-set under
XSLT 1.0 - My alternative don´t function
The node-set returned by the exsl:node-set() function will always contain a
single (document or root) node. Perhaps you wanted its children:
exsl:node-set()/*.
However, it's not clear to me that you need to create an RTF in the first
place. Why not define $filter as
<xsl:variable name="filter"
select="//RecursoEx1[($option=1 and F_FIN=$date1 and
contains(TITULO,'o'))
or ($option=2 and F_FIN=$date2)]"/>
Note also, that horrible bit of disable-output-escaping can be avoided by
setting the doctype-system and doctype-public attributes on xsl:output.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Alejandro [mailto:alexcontini(_at_)terra(_dot_)es]
Sent: 12 April 2008 13:05
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Cannot process a result tree fragment as a
node-set under XSLT 1.0 - My alternative don´t function
Hello, i want to recover any records in function of one
variable (option in this case), and i don´t know to do it. I
want to print the TITULO element the those records.
Can you help me, please?
Cheers,
Alexander
********************************* XML
*************************************
<?xml version="1.0"?>
<List>
<RecursoEx1>
<TITULO>Sara Baras</TITULO>
<F_INICIO>20080125000000</F_INICIO>
<F_FIN>20080211000000</F_FIN>
</RecursoEx1>
<RecursoEx1>
<TITULO>Exposicion de pintura</TITULO>
<F_INICIO>20080201000000</F_INICIO>
<F_FIN>20080211000000</F_FIN>
</RecursoEx1>
<RecursoEx1>
<TITULO>Inaguracion de ...</TITULO>
<F_INICIO>20080205000000</F_INICIO>
<F_FIN></F_FIN>
</RecursoEx1>
<RecursoEx1>
<TITULO>Clausura de ..</TITULO>
<F_INICIO>20080101000000</F_INICIO>
<F_FIN>20080205000000</F_FIN>
</RecursoEx1>
</List>
********************** XSL **********************
<?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet
xmlns:i18n="http://apache.org/cocoon/i18n/2.0";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:exsl="http://exslt.org/common";
extension-element-prefixes="exsl" version="1.0">
<xsl:output method="html" media-type="text/html;charset=iso-8859-1"
indent="yes" encoding="ISO-8859-1" omit-xml-declaration="yes" />
<xsl:variable name="date1" select="20080205000000"></xsl:variable>
<xsl:variable name="date2" select="20080211000000"></xsl:variable>
<xsl:variable name="option" select="1"></xsl:variable>
<xsl:template match="/">
<xsl:text disable-output-escaping="yes"><![CDATA[<!DOCTYPE
html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>]]></xsl:text>
<html xmlns="http://www.w3.org/1999/xhtml"; xml:lang="es">
<head>
<title>Gabinete of Prensa</title>
<meta http-equiv="Content-Type" content="text/html;
charset=iso-8859-1"
/>
</head>
<body>
<xsl:variable name="filter">
<xsl:choose>
<xsl:when test="$option=1">
<xsl:copy-of
select="//RecursoEx1[F_FIN=$date1 and
contains(TITULO,'o')]"/></xsl:when>
<xsl:otherwise>
<xsl:copy-of
select="//RecursoEx1[F_FIN=$date2]"/></xsl:otherwise>
</xsl:choose>
</xsl:variable>
<p>Number: <xsl:value-of
select="count(exsl:node-set($filter))"/></p> <!-- DON'T FUNCTION -->
<xsl:for-each select="exsl:node-set($filter)">
<p><xsl:value-of
select="exsl:node-set($filter)/TITULO"/></p> <!--
DON'T FUNCTION -->
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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