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Re: [xsl] Extracting value from node with formatter elements

2008-04-14 06:30:55
use <xsl:copy-of select="."/>

On Mon, Apr 14, 2008 at 5:22 PM, Amit Hanchinamani
<a(_dot_)hanchinamani(_at_)eurodata(_dot_)de> wrote:
Hi All,

 I am using XSLT 2.0 and parser Saxon.

 I am transforming some html tags to another tag format. I have span tags
which contain text value surrounded by formattere like bold, italic and
underline. The problem is when I try to extract the value of the node, it
always returns the text value without formatters <b>,<u> & <i>. The
following is the code:

 <xsl:template match="span" mode="copy">
       <xsl:variable name="elementText">
<xsl:value-of select="." />
       </xsl:variable>

 The input tag looks the following
 <span style="font-family:Times New Roman;font-size:12.0pt;"><b><u>blah
blah</u></b></span>

 I want to get the entire node value "<b><u>blah blah</u></b>". But using
<xsl:value-of select="." /> or <xsl:value-of select="text()"/> or
<xsl:value-of select="current()" /> returns only "blah blah". I cannot
figure out how to get the entire value along with the formatting tags.
 Any help appreciated.

 Regards,
 Amit


 .

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