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Re: [xsl] Nesting XPath predicates

2008-04-25 02:32:12
Liam Quin wrote:

  Hi

//service[(_at_)name = current()/serviceName]

That will work in the given example, but stops working if
you put that line inside a for-each...  or more precisely
works differently :-)

  Yes.  It will "work differently," exactly the same way your variable
will "work differently" if you put it in a for-each ;-)

  Regards,

--drkm























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