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[xsl] method transform (JAXP)

2008-05-08 01:49:47
Hello everybody!

I am using JAXP to execute templates.In the method transformer.transform , the

second parameter is one StreamResult. I can obtain the result in a File like

this:


File output = new File ("C:/Users/Izaskun/Desktop/workspace5/modelo/mayo.txt");
transformer.transform(new StreamSource(sourceId), new StreamResult(output));


I need to obtain the result in a var String because the result is only one line

and I dont know how to do it, because I tried a lot of forms but I dont obtain

this.

Could anybody help me?

Regards,

Izaskun




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