Thanks for the reply David. I'm using xslt 1 and this has solved most of
the problem. I just need to get the dates in order now.
Thanks again.
Jan
-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: 21 May 2008 15:36
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Variable containing unique values
I can't remember if you use xslt 1 or 2, in xslt2
select="distinct-values(//rolloverDate)" does what you ask.
But assuming you are using xslt 1 then getting unique values is the same
as grouping, and just using one of each group.
select="/rolloverDate[not(preceding::rolloverDate
an XML document can only have one top level element so
/rolloverDate
either matches that element (if the document element is rolloverDate) or
matches nothing. In either case the document eleemnt never has siblins
so the preceding::rolloverDate in the filter will never select anything.
You mean to select the child of the current element, so don't start with
/ which takes you to thetop of the tree:
select="rolloverDate[not(preceding::rolloverDate= current())]"/>
but note this will repeatedly look back over all earlier nodes so can be
quite slow on large sets, hence muenchian grouping.
<xsl:key name="e" match="element" use="rolloverDate"/>
...
<xsl:variable name="unique-dates">
<xsl:for-each
select
="REPORT/Rollover/RolloverForecast/summaryAccount/element[generate-id()=
generate-id(key('e',rolloverDate)[1])]">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
David
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