xsl-list
[Top] [All Lists]

Re: [xsl] how to assign part of an attributes value to another attribute within the same element?

2008-05-29 17:05:04

your stylesheet specified version="2.0" so I assume you are using an
xslt 2 system, in which case you have regexp available

    <xsl:template match="ptr[(_at_)target|@n]">
        <ptr target="{(_at_)target}" 
n="{replace(@target,'abc\.07\.7\.([0-9]+)[tf]m','$1')}"/>
    </xsl:template>

otherwise if you are using xslt 1 then

    <xsl:template match="ptr[(_at_)target|@n]">
        <ptr target="{(_at_)target}" 
n="{translate(substring(@target,10),'tfm','')}"/>
    </xsl:template>

David

________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.

This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs. 
________________________________________________________________________

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>