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RE: [xsl] Check the last character (XSLT V 2.0)

2008-06-16 06:41:50

Use the XPath 2.0 ends-with() function.

PS: the string "[#x0003F]" might mean "question mark" to you, but that's a
private convention. It doesn't mean that to the rest of us, and it's likely
to confuse everybody if you assume that everyone understands the meaning of
your data.

Michael Kay
http://www.saxonica.com/  

-----Original Message-----
From: Pankaj Chaturvedi [mailto:pankaj(_dot_)chaturvedi(_at_)idsil(_dot_)com] 
Sent: 16 June 2008 14:25
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Check the last character (XSLT V 2.0)


Hi,

I've snippet of markup which looks like below, wherein I am 
trying search that the string <articletitle> "ends" with 
question mark [#x0003F]. 

XML Snippet
===========

<articletitle>A team production theory of corporate 
law&quest;</articletitle>

XSLT
=====

<xsl:when test="contains(string(), '[#x0003F]')">
<!--  Do something  -->
</xsl:when>

The above code works perfect for the above snippet, but 
obviously fails for the below one as it does "contains" 
"?"/[#x0003F] but not "ends" with it. I was thinking using 
regular expression to check the last character but thought, 
taking suggestions to handle it in better way before getting 
my hands into it.


<articletitle>This is a sample&quest; Hello world</articletitle>


Any guidance will be highly appreciated.

Best,

Pankaj Chaturvedi

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