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Re: [xsl] Simple XML Diff

2008-07-11 09:00:55
I'm afraid I can't use extensions either. It has to work with most modern 
browsers and I have no control over the client environment.

So it isn't possible to loop through all elements and attributes in an XML and 
list all the elements attributes and their path?

e.g.
<nodeA att1="111">
 <nodeA1>AAA</nodeA1>
</nodeA>

Output:

/nodeA =
/nodeA/@att1 = 111
/nodeA/nodeA1 = FFF

This is the root of my problem, I don't know how to loop thorough everything 
and get it's absolute path

Regards

Mark

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