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[xsl] XPath and noname namespace

2008-07-14 07:52:40
Hello!

I have found workaround but I wonder why it must be done in that way..
Is it some kind of bug in XPath?

I have simple document:<svg xmlns="http://www.w3.org/2000/svg";>
<a>aadsf</a> </svg>

And now "//a" doesn't find a node.. I must use //*[local-name() =
'a'], but funny thing is that //*[name() = 'a'] works as well.. Why is
that?

Thanks,
Adam

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