What are you actually trying to do? The document f1.xml has only one document
element, so what is $id supposed to mean in document('f1.xml')/$id? If,
alternately, you want an element with the same name as $id, that's
*[local-name() eq $id]
-----Original Message-----
From: Greg Fausak [mailto:lgfausak(_at_)gmail(_dot_)com]
Sent: Wednesday, July 16, 2008 7:17 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] multiple input document question
Hi,
I'm wondering if there is any way to do the following:
<xsl:template match="*[(_at_)menu]">
<xsl:variable name="id" select="@id"/>
<xsl:for-each select="document('f1.xml')/$id">
...
I've tried all sorts of combinations.
I guess I can create an xslt output document
with the for-each statement selecting by the
value of the other document and just run
it through xslt twice. It just starts getting a little
weird then!
Thanks!
-g
--
Greg Fausak
greg(_at_)thursday(_dot_)com
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