You want 1 number but you are looping over <xsl:for-each
select="works_details">
and working out a number for each. As each works_details only has a
single "Work_Year child
Work_Year[last()] and Work_Year[1] are the same element, so you get 0 in
each case for the difference.
You want
<xsl:template match="artist_works">
<xsl:value-of select="
(works_details/Work_Year)[last()] - (works_details/Work_Year)[1]"/>
</xsl:template>
David
________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.
This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs.
________________________________________________________________________
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--