Garvin Riensche wrote:
Thanks for your answer. So, if my stylesheet only consists of one
template without an apply-templates:
<xsl:template match="node()">
...
</xsl:template>
I guess there's a build-in template with a call of apply-templates so
that this template is executed.
If my input is like
<a>
<b/>
</a>
the above template matches only <a> although <b> is also a node that is
"children of some parent". What's the reason for that?
The built-in template for the root nodes looks like this
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
see http://www.w3.org/TR/xslt#built-in-rule so it processes all child
nodes (which in your sample document is the 'a' element).
The a matching template for the 'a' element is used which is your
template above where you omitted the template body. If that does
<xsl:apply-templates/> respectively <xsl:apply-templates
select="node()"/> or <xsl:apply-templates select="*"/> then the 'b'
element is processed too.
--
Martin Honnen
http://JavaScript.FAQTs.com/
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