Cool, thanks Mukul, now how do I get the 2nd lowest?
-----Original Message-----
From: Mukul Gandhi [mailto:gandhi(_dot_)mukul(_at_)gmail(_dot_)com]
Sent: Friday, August 15, 2008 1:10 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Getting node w/ lowest attribute value
Please try this,
addresses/address[(@IsActive = 'true') and (@NumOrder =
min(../address[(_at_)IsActive = 'true']/@NumOrder))][1]
This uses the XPath 2.0 function, 'min'.
On Fri, Aug 15, 2008 at 11:22 PM, Bordeman, Chris
<Chris(_dot_)Bordeman(_at_)wolterskluwer(_dot_)com> wrote:
Hi all.
I have some nodes like:
<addresses>
<address IsActive="false" NumOrder=1>[...]</address>
<address IsActive="true" NumOrder=3>[...]</address>
<address IsActive="true" NumOrder=2>[...]</address> </addresses>
How do I get the first address node where IsActive=true AND has the
lowest value for the NumOrder attribute?
In the above case I'd want the 3rd address node (IsActive="true" and
NumOrder=2).
Any assistance would be appreciated. Thanks.
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