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Re: [xsl] XPath (regex?) question about $& in an XSLT stylesheet

2008-08-18 16:08:07
At 2008-08-18 15:46 -0700, Mark Wilson wrote:
I have an element
<Person>Benes (senior), Frances</Person>.

I can remove the '(senior)' from the data using
<xsl:value-of select="replace(., '\([a-zA-Z]+\)', ' ' )"/>

which gives me
<Person>Benes , Frances</Person>
but I want just the opposite:
<Person>(senior)</Person>

You can use regular expression groups in XSLT using unescaped parentheses. I hope the example below helps where I wrap the text before, in, and after as three groups. Creating the third group is unnecessary, but I left it in for completeness. You might need something more creative based on what you allow in your input.

. . . . . . . . . . Ken

t:\ftemp>type wilson.xml
<Person>Benes (senior), Frances</Person>

t:\ftemp>type wilson.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="2.0">

<xsl:template match="*">
  <xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
    <xsl:value-of select="replace(., '(.*)(\([a-zA-Z]+\))(.*)', '$2' )"/>
  </xsl:element>
</xsl:template>

</xsl:stylesheet>
t:\ftemp>xslt2 wilson.xml wilson.xsl con
<?xml version="1.0" encoding="UTF-8"?><Person>(senior)</Person>
t:\ftemp>



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