2008/8/19 Mark Wilson <mark(_at_)knihtisk(_dot_)org>:
All of the examples for using <xsl:result-document> to produce multiple
files (at least those that I've seen) write to a new file each time they
encounter a new instance of a controlling element structure in a 'list' and
use "position()" to help name the file. What technique do I apply to a
document containing a <List> of <Items> such as the one shown below? Here
the controlling element is not simply another <Year> element, but <Year>
elements with differing content: 1998, 1999 and so on, with each year
repeated within the source document many times. Ideally, the output would
be a series of files, one for each different <Year> content (1998.xml,
1999.xml) and each sorted internally by <IssueNumber> and <Page>.
I have not been able to see how the stylesheet should be constructed. Any
hints would be appreciated.
Thanks,
Mark
Source example:
<List>
<Item>
<Data>
...
</Data>
<Article>
<Year>1999</Year>
<IssueNumber>1</IssueNumber>
<Page>6</Page>
</Article>
</Item>
<Item>
.......
</Item>
</List>
How about:
<xsl:for-each-group select="Item" group-by="Article/Year">
<xsl:result-document href="{current-grouping-key()}.ext">
<xsl:for-each select="current-group()">
<xsl:sort select="Article/IssueNumber" data-type="number"/>
<xsl:sort select="Article/Page" data-type="number"/>
......
cheers
--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/
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