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Re: [xsl] generating xml from xslt

2008-08-26 12:13:44
Hi

Thanks for your help. Is there a quicker way of doing this instead of entering 
the value for the parameters everytime the transformation is run? I have xalan 
xslt processor. If I want to generate 50 files it will take a long time to run 
this transformaiton. 


--- On Tue, 8/26/08, Martin Honnen <Martin(_dot_)Honnen(_at_)gmx(_dot_)de> 
wrote:

From: Martin Honnen <Martin(_dot_)Honnen(_at_)gmx(_dot_)de>
Subject: Re: [xsl] generating xml from xslt
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Tuesday, August 26, 2008, 3:59 PM
Sarkup Sarkup wrote:

<xsl:stylesheet version="1.0" 

xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml"/>


Define three global parameters
   <xsl:param name="a1"/>
   <xsl:param name="a2"/>
   <xsl:param name="a3"/>
so that you can provide values for the transformation then
keep this 
template

 <xsl:template match="@*|node()">
  <xsl:copy>
   <xsl:apply-templates
select="@*|node()"/>
  </xsl:copy>
 </xsl:template>

remove the following template

<xsl:template
match="/root/status/locn/loc1/address">
<xsl:element
name="add1"></xsl:element>
<xsl:element
name="add2"></xsl:element>
<xsl:element
name="add3"></xsl:element>
</xsl:template>

and add three templates
   <xsl:template match="add1">
     <xsl:copy>
       <xsl:value-of select="$a1"/>
     </xsl:copy>
   </xsl:template>
   <xsl:template match="add2">
     <xsl:copy>
       <xsl:value-of select="$a2"/>
     </xsl:copy>
   </xsl:template>
   <xsl:template match="add3">
     <xsl:copy>
       <xsl:value-of select="$a3"/>
     </xsl:copy>
   </xsl:template>
-- 

      Martin Honnen
      http://JavaScript.FAQTs.com/

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