xsl-list
[Top] [All Lists]

Re: [xsl] Result tree fragment to string?

2008-08-27 12:56:27
Houghton,Andrew wrote:

Hmm... could he do something like:

<xsl:variable name="xml">
  <xsl:call-template name="serialize-tree">
    <xsl:with-param name="nodes" select="$result-tree" />
  </xsl:call-template>
</xsl:variable>

<xsl:template name="serialize-tree">
  <xsl:param name="nodes" />
  <xsl:apply-templates select="$nodes" mode="serialize" />


The above doesn't handle namespaces, processing-instructions, comments,
or mixed content, but it could be hacked to do so.  Is there a reason
why this approach would not work in XSL 1.0 to satisfy his needs?

Yes, the reason is that you can't do the apply-templates on the result tree fragment, you would first need to convert it to a node-set with an extension function.


--

        Martin Honnen
        http://JavaScript.FAQTs.com/

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--