In your match="/" template, the only apply-templates is to an element called
"ret". There is no element named ret in your source document. Therefore the
template rule with match="*" will never fire, therefore the code that
replaces "PENDING" by "1" will not be executed.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Mohit Anchlia [mailto:mohitanchlia(_at_)gmail(_dot_)com]
Sent: 08 September 2008 17:48
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] xsl: parsing through specific child nodes
So I tried various things but it doesn't seem to be working.
I'll give the complete information:
1. xml file:
<?xml version="1.0" encoding="UTF-8"?>
<Msg xmlns:ns2="http://www.abc.com/wsdl/v";>
<Msg>
<cid>103850015_0_1219420995471</cid>
<fid>41</fid>
<filing>IS</filing>
<State>PENDING</State>
</Msg>
</Msg>
2. xsl file:
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0"
exclude-result-prefixes="xmlns:ns2 ns2 xmlns"> <xsl:output
method="xml" indent="yes" /> <xsl:variable name="file2"
select="document('EFF')" /> <xsl:key name='PENDING'
match='Msg' use='./State'/> <xsl:template match="/">
<xsl:choose>
<xsl:when test="not(//State='PENDING')
and not(//State='SUCCEDED')">
<ret>
<xsl:copy-of select="//ret/*" />
</ret>
</xsl:when>
<xsl:when test="not($file2//State='PENDING')
and not($file2//State='SUCCEDED')">
<ret>
<xsl:copy-of select="$file2//ret/*" />
</ret>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="//ret"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="ret">
<xsl:apply-templates select="*"/> </xsl:template>
<xsl:template match="*"> <xsl:copy>
<xsl:choose>
<xsl:when test="text()='PENDING'">
<xsl:text>1</xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="." />
</xsl:otherwise>
</xsl:choose>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
3. Output:
<?xml version="1.0" encoding="UTF-8"?>
<Msg xmlns:ns2="http://www.abc.com/wsdl/v";>
<Msg>
<cid>103850015_0_1219420995471</cid>
<fid>41</fid>
<filing>IS</filing>
<State>PENDING</State>
</Msg>
</Msg>
4.expected output:
<?xml version="1.0" encoding="UTF-8"?>
<Msg>
<cid>103850015_0_1219420995471</cid>
<fid>41</fid>
<filing>IS</filing>
<State>1</State>
</Msg>
</Msg>
First I don't understand how there are 2 Msg nodes. And
second I wasn't able to get rid of namespace node by using
<element> as suggested by Michael, it's still copying the
namespace node.
On Mon, Sep 8, 2008 at 6:52 AM, Mukul Gandhi
<gandhi(_dot_)mukul(_at_)gmail(_dot_)com> wrote:
On Mon, Sep 8, 2008 at 1:16 AM, Mohit Anchlia
<mohitanchlia(_at_)gmail(_dot_)com> wrote:
1. So would above template mentioned by Mukul also output
node HIJ ?
I think, "outputting the node" is not the correct
terminology. We can
copy the node to the result tree, or write something else to the
result tree, derived from the properties of the input nodes.
<xsl:when test="local-name()="HIJ" and . = 'YYYYYY'">
This statement will probably not compile, as I can see some
misplaced quotes.
3. Currently I am using XSLT 1.0 and I am using JAXP which
uses Xalan.
How do I start using XSLT 2.0.
You need to download an XSLT 2.0 processor, like Saxon and
using it as
described in the documentation.
Would it just be matter of upping version in stylesheet node?
No. version="2.0" is just a hint to the processor. You need
to supply
the XSLT 2.0 stylesheet to a XSLT 2.0 processor like Saxon.
--
Regards,
Mukul Gandhi
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