(//para)[1]
and
/descendant::para[1]
are equivalent?
yes,
although of course the real expansion is
(/descendant-or-self::node()/child::para)[1]
but it comes to the same thing in this case.
note though that
(.//para)[1]
is not
./descendant::para[1]
it is
./descendant-or-self::para[1]
You don't need the -or-self variant in the form you posted though as in
that case you know the top node is / which can't be a para element.
David
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