G'day all,
I've got some XML that contains a list of items and groups, and each
group could contain either more items or more groups like so :
<catalog>
<item />
<group>
< group >
< item />
< item />
< group >
< group >
< item />
etc
So groups can contain either items or more groups or nothing. Items
only exist at the root (catalog) of this part of the tree or inside
groups. I'm outputting a single list of all of the items and group
currently using this :
<xsl:for-each select="item|descendant::group|descendant::group/item">
The reason for that is that a item node might also contain child nodes
that are also called <item> nodes that I don't want. I only want a
item node that has it's immediate parent a group node. (There may be
an easier way to do that...)
How do I count the "indent" level - so how many parent "groups" each
item or group has, right back up to the catalog node? Eg in the
example above, it would be 0 for the first item and group, 1 for the
next 4 etc.
I can change the for-each that I'm using, although it has to remain in
the same order, so I can't process them out of order.
Is the easiest way to count back up the tree for each one, or is there
a way to build that into the for-each? If I use count, how do I count
the path back up to the catalog node?
Thanks in advance,
Nick
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