yes, i am sorry. That was my mistake, of course, node_b shouldn't
appear in the output. But can you please post your solution as a hole
here, because i don't really know what you mean in the dotted area and
if i try your example like i understood it, than there is a huge
output which is not what i want.
<xsl:template match="/">
:(??)
<xsl:value-of
select="//*[descendant-or-self::*[contains(name(),'to_search')]]/name()"
separator=" "/>
</xsl:template>
</xsl:stylesheet>
Regards,
Jonas
2008/9/29 David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>:
I want to search for all nodes which for this example contain the
phrase "to_search" and than i want to ascend from the found node
accross the ancestor-or-self axis to output every parent but in the
order as they appear in the xml sourc
well that sounds like
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
:
<xsl:value-of
select="//*[descendant-or-self::*[contains(name(),'to_search')]]/name()"
separator=" "/>
</xsl:template>
</xsl:stylesheet>
but that doesn't produce your requested output, it produces
$ saxon9 nodesearch.xml nodesearch.xsl
<?xml version="1.0" encoding="UTF-8"?>
:
node_a
node_c
node_d
node_c
node_e
node_c
node_i
node_c
node_l
node_c
node_v
node_d
node_c
node_q
node_c
node_d
node_u
node_c
node_l
node_c
node_d
node_c
node_l
node_c
node_i
node_to_search_1
node_c
node_s
node_c
node_d
node_c
node_to_search_2
you requested node_b but that has no descendant "search" node so I
don't see why it should be output?
David
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