Is there a way to use my $thePath variable, instead of including the
directory path inside the @filename attribute?
yes:
<docs path="jb">
<doc filename="wine1.xml" />
<doc filename="wine2.xml" />
<doc filename="wine3.xml" />
...
</docs>
<xsl:template match="docs">
<xsl:variable name="p" select="document(concat(@path,'/',doc[1]/@filename))"/>
<xsl:variable name="z" select="document(doc/@filename,$p)"/>
<xsl:for-each select="$z">
: <xsl:value-of select="."/>
</xsl:for-each>
</xsl:template>
puts all the document nodes in $z.
Secondly, I'm not sure I fully understand what my $theWines variable now
contains. I believe it is a collection of tree fragments--i.e. there's
no single top-most node, is that right? Or is there an implicit /
(document) node?
No, ots a set of element nodes, each of which has a (different) root
node (/) as parent.
The reason I ask is because I have some templates that rely on
processing the preceding axis, and whereas my templates work fine for my
< wines > xml file, they do not produce the anticipated results when
using my $theWines variable.
Yes, nodes in different documents are not related by any axis.
David
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