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RE: [xsl] Saxon node matching order

2008-11-28 10:36:03
In my tests, your code produces exactly the output you are asking for.

Michael Kay
http://www.saxonica.com/
 

-----Original Message-----
From: Ed Yau [mailto:eyau(_at_)vstrading(_dot_)co(_dot_)uk] 
Sent: 28 November 2008 14:50
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Saxon node matching order

Hi all,

I have a question about how Saxon chooses which node to match next.

I have some XML that looks a bit like this:

<x>
   <y>
      <z>Peter</z>
   </y>
   <z> </z>
   <y>
      <z>Jones</>
   </y>
</x>

What I'm trying to achieve is the follow:

<x>
      <z>Peter</z>
      <z> </z>
      <z>Jones</>
</x>

With the code below:

<xsl:template match="x" >
      <xsl:apply-templates select="y|z"/>
</xsl:template>

<xsl:template match="y">
      <xsl:apply-templates select="z"/>
</xsl:template>
      
<xsl:template match="z">
      <xsl:copy-of select="."/>
</xsl:template>

<xsl:template match="@*|*">
     <xsl:copy>
        <xsl:apply-templates select="@*|node()">
        </xsl:apply-templates>
     </xsl:copy>
  </xsl:template>


But annoyingly my code seems to be doing this instead:

<x>
      <z>Peter</z>
      <z>Jones</z>
      <z> </z>
</x>

It is obviously matching all the <y> tags before the <z> tags.
Does anyone know of a way around this?

Many thanks,
   Ed









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