[xsl] Re: populate nodelist variable with a variable in select statement

Hi Michael, David,
Thanks for the suggestions and clarifying my questions.
Will try the extension route.
 
 Thanks

> --- On Mon, 12/1/08, Lara Brian <lara_bc(_at_)yahoo(_dot_)com>
> wrote:
>
> > From: Lara Brian <lara_bc(_at_)yahoo(_dot_)com>
> > Subject: populate nodelist variable with a variable in
> select statement
> > To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> > Date: Monday, December 1, 2008, 4:45 PM
> > Hi,
> > I am trying to populate a variable with a nodelist
> that
> > takes a variable in its select statement.
> >
> > For example,
> > <xsl:variable name="myNodeSet"
> > select="site/assets/asset[(type/@code =
> 'aaa')
> > and starts-with(@vpath,'my/path/')  and
> > (lang='us_en') and $SEARCH_STRING]"/>
> >
> > and SEARCH_STRING is defined as
> > <xsl:param
> > name="SEARCH_STRING"> and (
> (related/@code =
> > '111') or
> > (related/@code = '222') or (related/@code =
> > '333') )</xsl:param>
> >
> > My xml is of the form,
> > <site>
> > <assets>
> > <asset vpath="my/path/and/more">
> > <lang>eng</lang>
> > <featured-item>No</featured-item>
> > <type code="aaa"/>
> > <related code="111"/>
> > <related code="777"/>
> > </asset>
> > <asset>
> >   ...
> > </asset>
> > </assets>
> > <site>
> >
> > Is
> > this even possible? I can do this using <xsl
> choose>
> > and checking
> > each condition and setting the variable accordingly,
> but in
> > future if i
> > have more conditions for the variable, i need to add
> more
> > conditions in
> > all my xsls. It would be nice if i can set this
> variable in
> > one place
> > and then use it use it as a replace string.
> >
> > Thanks for any help or pointers in this regard.



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