Thanks for the warning, Ken. I'll scratch that approach off my list.
This is great, Michael! If I can sort the <word-group>s in some standard
way (alphabetically?) across all the places, I should be able then to
group the data processed from your xsl based on how many places have a
given <word-group>.
G. Ken Holman wrote:
At 2008-12-10 18:42 -0600, Quinn Dombrowski wrote:
Thanks for looking at this! Sorry for not being as clear as I
could've been with what I'm looking for. For the example data set,
I'm trying to automatically generate an output something like this:
Aa + C + Qqq: 2 places (1, 3)
Aa + C: 3 places (1, 2, 3)
Aa + Zz: 2 places (2, 3)
C + Qqq: 2 places (1, 3)
So it lists all the groups of 2+ words that appear together in 2+
places. This list is sorted by length of the group (3 words is the
maximum number of words that occurs in 2+ places in the sample data),
but it'd be nice to also be able to sort by number of places:
Aa + C: 3 places (1, 2, 3)
Aa + Zz: 2 places (2, 3)
etc.
Sorry, that would be beyond my volunteer allocation for this morning
... too much going on right now.
I was using intersects to get places with Aa AND C AND Qqq
(<xsl:value-of
select="count(atlas/place/place_number[../words/word='Aa'] intersect
atlas/place/place_number[../words/word='C'])"/>), but got overwhelmed
by the number of ways I'd have to plug in all the different words to
go through the data exhaustively-- the real data has 250+ places and
75+ words.
But for you and the archive, be aware that your concept of intersect
above wouldn't help in the case of XSLT 2.0:
$a intersect $b
returns those tree nodes in node set $a that are the same tree nodes
found in node set $b ... not by value, but the nodes themselves.
For this reason an "Aa" node in place 1 would not be recognized as
being the same as the "Aa" node in place 2 and would not be returned
in an intersection.
I hope this steers you away from an unsuccessful approach.
. . . . . . . . . Ken
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