[xsl] cross reference call of templates in xslt

Hi,
I have a XSL-Stylesheet:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; 
xmlns:xdo="http://www.xdomea.de";>
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes" /> 
        
        <xsl:template match="/"> 
                <xsl:for-each select="/X">
                        <X>
                                <xsl:for-each select="/XDOMEA/Dokument">        
                                        <Dokument>
                                                <xsl:call-template 
name="dokument"/>
                                        </Dokument>
                        </X>
                </xsl:for-each>
        </xsl:template>

        <xsl:template name="dokument">
                <Primaerdokument>
                        <xsl:copy-of select="./Primaerdokument/Dateiname"/>
                </Primaerdokument>                      
                <xsl:call-template name="AdressenInfo" />       
        </xsl:template> 

        <xsl:template name="AdressenInfo">
                <xsl:if test="./Adress_Informationen/Absender/Referenz">
                        <xsl:apply-templates 
select="/XDOMEA/Adresse"><xsl:with-param name="referenceID" 
select="./Adress_Informationen/Absender/Referenz" /></xsl:apply-templates>
                </xsl:if>
        </xsl:template>

        <xsl:template name="adresse">
                <xsl:param name="referenceID" />
                        <Name_ID><xsl:value-of select="./Name/Name_ID" 
/></Name_ID>
                                <adr_name><xsl:value-of 
select="./Name/Nachname" /></adr_name>
                                <adr_anrede><xsl:value-of 
select="./Name/Anrede" /></adr_anrede>
                        </Adresse>
                </xsl:if>       
        </xsl:template>
</xsl:stylesheet>


My XML-File as Input:
<?xml version="1.0" encoding="UTF-8"?>
<X>
  <Daten>
    <Dokument>
      <Primaerdokument>
        <Dateiname>test.txt</Dateiname>
     </Primaerdokument>
      <Adress_Informationen>
        <Absender>
          <Referenz>d1139077-ed5b-4be8-9eaa-775ab4052c5c</Referenz>
        </Absender>
      </Adress_Informationen>
    </Dokument>
    <Adresse>
      <Name>
        <Name_ID>1234567890</Name_ID>
        <Anrede>a</Anrede>
      </Name>
      <Anschrift>
        <Strasse>i</Strasse>
      </Anschrift>
    </Adresse>
  </Daten>
</X>


Now my Result:
?xml version="1.0" encoding="UTF-8"?>
<X>
<Dokument>
<Primaerdokument>
<Dateiname>test (080011538) (080011547).txt</Dateiname>
</Primaerdokument>
 
        1234567890
        a
        i
 </Dokument>
 </XDOMEA>


So i need the information of the part of "Adresse" put into the part of 
"Primaerdokument".

I need the following result:
?xml version="1.0" encoding="UTF-8"?>
<X>
<Dokument>
<Primaerdokument>
<Dateiname>test (080011538) (080011547).txt</Dateiname>
</Primaerdokument>
<Name_ID>1234567890</Name_ID>
<adr_name>a</adr_name>
<adr_anrede>i</adr_anrede>
 </Dokument>
 </XDOMEA>


So: Is it possible to do with XSLT what i need? And what do i need to change in 
my XSLT-File? I'm doing the Transformatino in Java with 
javax.xml.transform.Transformer

Thanks and kind regards.


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