If for example $seq contains elements a, b, c, b, e:
how do I select
A - everything before the first b
B - everything from the first b to the end
C - the position of the first b?
You don't actually say whether this is 1.0 or 2.0, but since you're talking
sequences rather than node-sets, I assume 2.0. The following might not be
the best solution, but works:
<xsl:variable name="index" as="xs:integer*">
<xsl:for-each select="$seq">
<xsl:if test="self::b">
<xsl:sequence select="position()"/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
then
A - $seq[position() lt $index[1]]
B - $seq[position() ge $index[1]]
C - $index[1]
The details of course depend on what you want to happen if there is no b
element in the sequence.
Alternatively
<xsl:for-each-group select="$seq" group-starting-with="b">
might do what you want - but it depends exactly what you want to do.
Michael Kay
http://www.saxonica.com/
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