^[ will match a bracket only if it appears right at the start of the text
node, but in your case the bracket is preceded by whitespace.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Byomokesh Sahoo [mailto:sahoo(_dot_)byomokesh(_at_)gmail(_dot_)com]
Sent: 31 December 2008 09:16
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Regex and apply xsl number
Hi,
I am getting problem in regex search in text node. Here my XML
<file xmlns:QL="http://www.xmltricks.com">
<QL:PARCITE/>
33 C.L.A.S. 505
<QL:QLCITE/>
[1994] O.L.A.A. No. 467
[para1] The grievance.
[para2] The grievance.
[para3] The grievance.
<QL:QLCITE/>
[1994] O.L.A.A. No. 467
[para5] The grievance. <!-- Need [para4] not [para5]
sequence number -->
[para6] The grievance. <!-- Here should be [para5] -->
<!-- continue like this where [para is found. --> </file>
Desired Output
=============
<file xmlns:QL="http://www.xmltricks.com">
<QL:PARCITE/>
33 C.L.A.S. 505
<QL:QLCITE/>
[1994] O.L.A.A. No. 467
[para1] The grievance.
[para2] The grievance.
[para3] The grievance.
<QL:QLCITE/>
[1994] O.L.A.A. No. 467
[para4] The grievance.
[para5] The grievance.
</file>
My XSL ==
<xsl:variable name="myregex">((^[)(\w*)(\d*))</xsl:variable>
<xsl:variable name="ss"><xsl:number/></xsl:variable>
<xsl:template match="text()">
<xsl:analyze-string select="." regex="$myregex">
<xsl:matching-substring> <xsl:value-of select="$ss"/>
</xsl:matching-substring> <xsl:non-matching-substring>
<xsl:value-of select="."/>
</xsl:non-matching-substring>
</xsl:analyze-string>
===
I want to transform only sequence number (like 1, 2, 3) in
[para] text. I am trying but not able to match and replace to
sequence number.
Thanks
Byomokesh
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