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[xsl] Table Span not working

2009-01-05 22:45:27
Hi List,

I am doing XSL style sheet for XML view. In table, span not able to get,
Please correct me any mistake in the below code.

 XSL
=====
The below my code not giving expected result/span in IE.

    <xsl:template match="thead/row/entry">
        <xsl:variable name="colst" select="translate(@namest,'col','')"/>
        <xsl:variable name="colend" select="translate(@nameend,'col','')"/>
        <th bgcolor="#C4C4FF"
colspan="($colend-$colst)+1"><xsl:apply-templates/></th>
    </xsl:template>

 XML
======
Four column table contains a header spanned row like below. 

<row row-type="straddle-head">
<entry align="center" nameend="col3" namest="col2">PIN-a &#x0394;&#x03C0;
(mN/m)</entry>
<entry align="center" nameend="col5" namest="col4">PIN-b &#x0394;&#x03C0;
(mN/m)</entry>
</row>

Regards,
Ramkumar


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