William Warby wrote:
I want to group nodes in an XML file, placing a heading above each
category. The category is defined in an attribute which may be the same
for a series of records. The code sample below shows what I want to do.
I've been going round in circles trying combinations of variables,
templates, for-each loops and I just can't seem to get a handle on the
problem. Any help would be very gratefully received.
Here is an XSLT 1.0 stylesheet that uses Muenchian grouping:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="html" indent="yes"/>
<xsl:key name="cat"
match="book"
use="concat(parent::author/@name, '|', @genre)"/>
<xsl:template match="/">
<html lang="en">
<head>
<title>Books</title>
</head>
<body>
<h1>Books</h1>
<xsl:apply-templates select="authors/author"/>
</body>
</html>
</xsl:template>
<xsl:template match="author">
<h2>
<xsl:value-of select="@name"/>
</h2>
<xsl:apply-templates select="book[generate-id() =
generate-id(key('cat', concat(parent::author/@name, '|', @genre))[1])]"
mode="group"/>
</xsl:template>
<xsl:template match="book" mode="group">
<h3>
<xsl:value-of select="@genre"/>
</h3>
<ul>
<xsl:apply-templates select="key('cat',
concat(parent::author/@name, '|', @genre))"/>
</ul>
</xsl:template>
<xsl:template match="book">
<li>
<xsl:value-of select="@name"/>
</li>
</xsl:template>
</xsl:stylesheet>
Read more about that on http://www.jenitennison.com/xslt/grouping/index.xml
--
Martin Honnen
http://JavaScript.FAQTs.com/
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