Hi everyone,
I am using XSLT 2.0 and I have three questions about an ordered list in this
format:
<root>
<H1>Heading</H1>
<P>List Heading</P>
<P>A. One big</P>
<P>sentence incorrectly</P>
<P>placed in P tags</P>
<P>B. Another long</P>
<P>sentence spanning P tags.</P>
<P>C. This should really</P>
<P>be one</P>
<P>long</P>
<P>list item</P>
<P>that spans randomly.</P>
<P>Hopefully I am some unrelated text.</P>
</root>
Which I want converted to this format:
<root>
<H1>Heading</H1>
<P>List Heading</P>
<OL>
<LI>One big sentence incorrectly placed in P tags.</LI>
<LI>Another long sentence spanning P tags.</LI>
<LI>This should really be one long list item that spans
randomly.</LI>
</OL>
<P>Hopefully I am some unrelated text.</P>
</root>
Due to the original XML file being rather bad the list may not start at A.
Before I have been able to catch a numbered list just by checking if the P
tag starts with a number and its preceding sibling does not, then when I am
inside the list check if the next P tag starts with a number a well. This
list is different though.
1) I imagine you can check if the P tags starts with a letter by doing
something like this:
P[starts-with(translate(., 'vUppercaseChars_CONST',
'vUppercaseAChar_CONST'), 'A')]
How would you then check it begins with letter followed by a dot?
2) Is it possible to find a letter followed by a dot then check if the next
P node starts with the next letter of the alphabet followed by a dot?
3) Is it possible to check if the next 10 P tags contain the next letter of
the alphabet plus a dot. Previously I have been able to pick up lists no
problem when they had a predictable pattern but this one doesn't. I can only
assume that the list ends after about 10 P tags or it finds a character in a
previous position in the alphabet or it hits some other tag that is not a P
tag. I would end the list item at the first full stop it found after the
last P tag that started with character plus a dot. Is something like this
possible in XSLT and if so how?
Thanks for your time,
Graeme
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