--------------------------------------------------
From: "J. S. Rawat" <jrawat(_at_)aptaracorp(_dot_)com>
Sent: Friday, January 16, 2009 10:00 AM
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>;
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: Re: [xsl] read directory and get it as an array
At 12:20 PM 1/16/2009, Mukul Gandhi wrote:
The variable 'file-collection' will contain a sequence of nodes
But I need names of the files within a directory.
ABC
a.xml
b.xml
I want to a.xml and b.xml should be hold as an array. Below is perl code
for doing the same.
opendir (DIR, "ABC");
while($filename = readdir(DIR))
{
push (@filearray, $filename);
}
closedir(DIR);
for ($i=3; $i<=$#filearray; $i++)
{
open(INFILE, "<ABC/$filearray[$i]");
But XML/XSLT doesn't have 'arrays'. So if you want to deal with a collection
of files from within XSLT you can use 'collection,' if you want to deal with
them in a another language then use that language's constructs. I don't see
where collection lets you down given an XSLT scenario.
Joe
http://joe.fawcett.name
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