[xsl] Get position of parent

Hello List,

What is the best way to get the position of a parent node? In the below xml,
assume my context node is para:

/table/tgroup/tbody/row/entry[1]/para

If my context node is para, how do I get the position of its parent entry?

<table frame="all" align="center" id="C-TABLE3" width="90%">
        <title>Title</title>
        <tgroup cols="3">
                <colspec colnum="1" colname="spycolgen1" colwidth="*"/>
                <colspec colnum="2" colname="spycolgen2" colwidth="*"/>
                <colspec colnum="3" colname="spycolgen3" colwidth="*"/>
                <tbody>
                        <row>
                                <entry>
                                        <!--get position of parent::entry-->
                                        <para id="table3-para 1">context
node</para>
                                </entry>
                                <entry>
                                        <para>test</para>
                                </entry>
                                <entry>
                                        <para>test</para>
                                </entry>
                        </row>
                </tbody>
        </tgroup>
</table>




Thanks
Phil



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