You can handle that by extending the from condition, for example
from="level1|section".
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Spencer Tickner [mailto:spencertickner(_at_)gmail(_dot_)com]
Sent: 20 January 2009 00:22
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] <xsl:number> starting at a preceding-sibling
Thank you very much for the response Dr. Kay,
Unfortunately as I expected level="single" and level="any" to
work the same way in regards to from I made my example
document less robust than it probably should have been. With
level="any" the revised xml
source:
<root>
<section>
<level1></level1>
<level1></level1>
<level2></level2>
<level3></level3>
<level2></level2>
<level1></level1>
<level2></level2>
<level3></level3>
</section>
<section>
<level1></level1>
</section>
</root>
would come out:
<root>
<section>
<level1>1</level1>
<level1>2</level1>
<level2>a</level2>
<level3>i</level3>
<level2>b</level2>
<level1>3</level1>
<level2>a</level2>
<level3>i</level3>
</section>
<secton>
<level1>4</level1>
</secton>
</root>
When the second section should start renumbering itself yet
again to 1 not 4. Once again my apologies for an inadequate test case.
Spencer
On Mon, Jan 19, 2009 at 4:04 PM, Michael Kay
<mike(_at_)saxonica(_dot_)com> wrote:
Try this:
<xsl:template match="level1">
<xsl:copy>
<xsl:number level="any" from="root" format="1"/> </xsl:copy>
</xsl:template>
<xsl:template match="level2">
<xsl:copy>
<xsl:number level="any" from="level1" format="a"/> </xsl:copy>
</xsl:template>
<xsl:template match="level3">
<xsl:copy>
<xsl:number level="any" from="level2" format="i"/> </xsl:copy>
</xsl:template>
The surprise here (and it took me a while to grasp it) is
that level="any"
is needed even though you're counting siblings. This is
because the "from"
pattern doesn't work the way you want it to with level="single".
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Spencer Tickner [mailto:spencertickner(_at_)gmail(_dot_)com]
Sent: 19 January 2009 23:04
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] <xsl:number> starting at a preceding-sibling
Hi List and thanks in advance for the help.
I'm attempting to number some flat xml using xslt 2.0 and am
struggling a bit. Given:
<root>
<level1></level1>
<level1></level1>
<level2></level2>
<level3></level3>
<level2></level2>
<level1></level1>
<level2></level2>
<level3></level3>
</root>
I need to number each level based on it's preceding-sibling so it
would look like:
<root>
<level1>1</level1>
<level1>2</level1>
<level2>a</level2>
<level3>i</level3>
<level2>b</level2>
<level1>3</level1>
<level2>a</level2>
<level3>i</level3>
</root>
Counting <level1> is easy with <xsl:number> but the template for
<level2> and <level3>. Stylesheet is below, template for
level3 is ommited as it will hinge on solving the template
for level2
(I know all the variables are pretty ugly):
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="level1">
<xsl:copy>
<xsl:number count="level1" level="single" format="1"/> </xsl:copy>
</xsl:template>
<xsl:template match="level2">
<xsl:variable name="cousins" select="preceding-sibling::*"/>
<xsl:variable name="num">
<xsl:value-of
select="count($cousins[last()]/preceding-sibling::*[not(follow
ing-sibling::level1)][name()
= 'level2'])"/>
</xsl:variable>
<xsl:variable name="renum">
<xsl:choose>
<xsl:when test="$cousins[last()]/name() =
name(.)"><xsl:value-of
select="number($num) + 2"/></xsl:when>
<xsl:otherwise><xsl:value-of
select="number($num) + 1"/></xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:copy>
<xsl:number value="$renum" format="a"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Any advice would be appreciated.
Thanks,
Spencer
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