Hi List,
I want to avoid xmlns="http://www.w3.org/1999/xhtml"; as an attribute
of element "item" (<itemref xmlns="http://www.w3.org/1999/xhtml";
idref="ch1" linear="yes"/>) from the output xml even after my
exclusion entry in the top (#default). If I remove xmlns from
xsl:stylesheet, I am getting xmlns="".
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns="http://www.w3.org/1999/xhtml";
exclude-result-prefixes="#default xsl" version="2.0">
<xsl:variable name="metafile" select="document('meta.txt')"/>
<xsl:for-each select="$metafile/items/file">
<xsl:apply-templates select="." mode="manifest"/>
</xsl:for-each>
<xsl:template match="file" mode="manifest">
<item id="{title/@id}" href="{(_at_)id}" media-type="application/xhtml+xml"/>
</xsl:template>
Any tip in this direction will be highly appriciable!!!
Thanks
...JSR
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