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RE: [xsl] most efficient way to get XML source's parent dir path

2009-02-11 11:02:42

Well, I tried to simplify the example. In reality, I am using 
the unparsed-text function which has no base-uri argument () 
and the resolver is provided with a full java.net.URI so I 
needed a way to create the correct path in the XPath. I 
should have been more clear.

Am I still missing something?


You should definitely be using functions like base-uri() and resolve-uri()
rather than trying to manipulate the URI "by hand".

Michael Kay
http://www.saxonica.com/


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