Always insightful! Thanks all for the help on this. As usual, the
result/behavior is quite expected.
Karl..
On Fri, Feb 20, 2009 at 4:44 AM, Jesper Tverskov
<jesper(_dot_)tverskov(_at_)gmail(_dot_)com> wrote:
I guess this is the proper solution then:
<xsl:character-map name="x">
<xsl:output-character character=" " string="&#160;"/>
</xsl:character-map>
<xsl:output indent="yes" use-character-maps="x"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Cheers,
Jesper Tverskov
http://www.xmlkurser.dk
http://www.xmlplease.com
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