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RE: [xsl] Fwd: using xquey in XSLT transformation

2009-03-18 19:52:43
You can declare your own functions in XSLT 2.0:


<xsl:stylsheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
    xmlns:xs="http://www.w3.org/2001/XMLSchema";
    xmlns:local="your-namespace"
    version="2.0">
    <xsl:function name="local:getPic">
            <xsl:param name="node" as="node()"/>
            <xsl:param name="searchValue" as="xs:string"/>

        <xsl:choose>
            <xsl:when test="empty($searchvalue)">
                <xsl:sequence select="$node/pic-value"/>
            </xsl:when>
            <xsl:otherwise>
                <xsl:sequence
select="local:ref($node//data-declaration[name=$searchvalue[1]], 
$searchValue[postion()
!= 1])"/>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:function>
<xsl:stylesheet>

Cheers,


Jim Earley
Senior XML Architect
Flatirons Solutions Corp.
 
The important thing is not to stop questioning. Curiosity has its own reason for
existing - Albert Einstein

-----Original Message-----
From: Michalmas [mailto:michalmas(_at_)gmail(_dot_)com] 
Sent: Wednesday, March 18, 2009 4:27 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Fwd: using xquey in XSLT transformation

Hello guys,

I have XQuery function. I need to use it in XSLT transformation. Is it possible?

d e c l a r e func t i on l o c a l : g e tPic ( $node as node ( )  ,
$ s ear chValue as x s : s t r i n g   )
 {
 i f ( empty ($ searchValue ) ) then
    $node/ pic-value

 e l s e
      l o c a l : r e f ($ node // de s c endant : :da ta-d e c l a r a t i o n
      [ name=$s earchValue [ 1 ] ] [ 1 ] ,
      $ searchValue [  p o s i t i o n ( )  !=  1 ] )
 };

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