I could use help with problem that I just don't seem to have the
programming chops to conquer. I don't have template for anyone to
analyze, I can't seem to get to that state. I'm using XSL 1.0.
Here is my conundrum:
I have an element <HYPERTEXT>, that has an attribute called "linkend".
The value of "linkend" corresponds to an ID attribute on an element
further up the tree (preceding). This element is named <nameloc>. This
element has a child, <nmlist>. My goal is to convert <HYPERTEXT> to
<link> (easy enough). But my problem is I can't seem to write an
expression (xsl:if? xsl:when?) to can go find the <nameloc> element that
has the corresponding ID, then get the text of <nmlist> as the value of
an "item" attribute on <link>.
The following are just snippets of XML. The entire tree structure should
be irrelevant. Also, the <nameloc> and <nmlist> elements are eliminated
in the results (not converted or output).
Current XML:
<document>
<nameloc id="M05-08.-HT2">
<nmlist nametype="element" dtdorlpd="REAR" docorsub="APPX-F"
elemtype="ROW">item1</nmlist>
</nameloc>
<STEP>
<HYPERTEXT linkend="M05-08.-HT2">Service
air cleaner assembly.</HYPERTEXT>
</STEP>
</document>
The result I need to create is this:
<step>Service air cleaner assembly.<link item="item1"></step>
How do I write a test will get me text of <nmlist> based on the
comparison of "linkend" and "id"?
Thanks.
C. Flanders
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