My apologies for being rather vague with the "doesn't work".
Yes, I'm using 1.0, and your solution seems to be working like a charm.
Thank you for your help, really appreciate it!
----- Original Message -----
From: "Martin Honnen" <Martin(_dot_)Honnen(_at_)gmx(_dot_)de>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, March 26, 2009 1:33 PM
Subject: Re: [xsl] Need help skipping a child element
Fatbob wrote:
I tried doing...
<xsl:for-each select="Cell[position() = (1,2,3,6,7)]">
but that doesn't work.
"doesn't work" does not tell us what happened. Do you get an error as
you are using an XSLT 1.0 processor? Then try
<xsl:for-each select="Cell[position() = 1 or position() = 2 or
position() = 3 or position() = 6 or position() = 7]">
--
Martin Honnen
http://JavaScript.FAQTs.com/
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