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RE: [xsl] Iterate through tree structure

2009-03-31 12:04:50
Hi,

Can you explain the requirements further? Why should the result
have dir1 dir2 and dir4 in the first ul and not dir3? Why does
dir3 not appear in the result? And why do dir4 and dir5 need
to be in a separate ul?

It would be straightforward to list all dirs "above" a given
page, but if one needs to filter some of them out and/or
organize them in a different system than the source, one
needs instructions ;-)

Regards,
EB

-----Original Message-----
From: jim mcgovern [mailto:jim(_dot_)mcgovern2(_at_)googlemail(_dot_)com]
Sent: Tuesday, March 31, 2009 5:29 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Iterate through tree structure


Hi there

Apologies for the duplicate post but I sent this through hotmail
earlier and it stripped the content.  Hopefully this will be more
successful...

Hopefully someone can help me with something that I thought was going
to be straight forward but has been giving me a few problems!

I'm trying to generate navigation from an xml file which is pretty
much as below:-

<dir name="dir1" id="x1">
 <page pname = "page1"></page>
 <dir name="dir2" id="x2">
   <page pname = "page2"></page>
  <dir name="dir3" id="x3">
    <page pname = "page3"></page>
  </dir>
  <dir name="dir4" id="x4">
    <page pname = "page4"></page>
   <dir name="dir5" id="x5">
     <page pname = "page5"></page>
     <page pname = "page6"></page>
    <dir name="dir6" id="x6">
      <page pname = "page6"></page>
    </dir>
   </dir>
  </dir>
 </dir>
</dir>

The above is a snapshot as it can go down "n" levels.  If I'm at page6
then my navigation needs to be:-

<ul>
  <li>dir1</li>
  <li>dir2</li>
  <li>dir4</li>
</ul>
<ul>
  <li>dir5</li>
  <li>dir6</li>
</ul>

What I'm having difficulty with is how to close the opening ul and
open a new ul when I'm a directory up from the directory level I'm
actully on.



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