Michael,
you are absolutely right. I'm sorry.
Thanks,
e.
2009/4/14 Michael Kay <mike(_at_)saxonica(_dot_)com>:
<xsl:template match="param[(_at_)name=' { $p } ']"> <xsl:text>{
but it doesn't work! What other am I missing?
Please, never say "it doesn't work". Say how it fails (exactly how).
Otherwise we have to stare at your code to see if we can spot what's wrong.
In this case it's fairly obvious, though: you NEVER use curly braces in an
XPath expression or XSLT match pattern. This should be:
<xsl:template match="param[(_at_)name=$p]">
That's legal in XSLT 2.0 but not in 1.0 (in 1.0, patterns can't contain
variable references).
Michael Kay
http://www.saxonica.com/
Vasu, this my question should answer to your one! :)
Thanks again!!!!
e.
2009/4/14 Vasu Chakkera <vasucv(_at_)gmail(_dot_)com>:
<Catalog>
<Id> newvalue </Id>
</Catalog>
where will you get this "newvalue" from ? Presumably it
wont be in the
XML.. or will it?
Vasu
2009/4/14 Emiliano Pecis <emiliano(_dot_)pecis(_at_)gmail(_dot_)com>:
Hi All,
I'm using latest version of Stylus Studio, to develop a
XSLT (based
on Saxon 9.0.1.5 processor) to do the following simple (should be)
transformation.
From XML:
<GetCatalog>
<ListOfCatalog>
<Catalog>
<Id> <param name="same/new">foo</param> </Id>
</Catalog>
</ListOfCatalog>
</GetCatalog>
The destination must depends on "name" attribute of param
element. If
name="same" the following XML must be returned:
<GetCatalog>
<ListOfCatalog>
<Catalog>
<Id> foo </Id>
</Catalog>
</ListOfCatalog>
</GetCatalog>
Otherwise:
<GetCatalog>
<ListOfCatalog>
<Catalog>
<Id> newvalue </Id>
</Catalog>
</ListOfCatalog>
</GetCatalog>
In both cases <param> element has to be removed.
Now, I have two issues. First of all the management of this
"parameters".Secondly, every xml elements (GetCatalog,
ListOfCatalog,
etc etc) could change: only tag "param" will be the same.
Thanks a lot in advance,
emiliano
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Vasu Chakkera
Numerical Algorithms Group Ltd.
Oxford
www.vasucv.com
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