xsl-list
[Top] [All Lists]

Re: [xsl] How to cast current-group() ?

2009-04-28 11:34:20

as Michael said the problem isn't so much the schema typing as the fact
that you are passing a string when the function expects an element.
this fails
 as="schema-element(res:team)"  
but so would
    as="element()"

Your function expects a team element so just give it one instead of a
string, there will (presumably) necessarily be a team element child of
the current node in a valid document so

  <xsl:copy-of select="myfn:MakeTableRow(team,current-group())"/>

should work and be able to cope with any typing of the first parameter.

David

________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.

This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs. 
________________________________________________________________________

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--