Variable references such as $toLang can be used in place of literal values.
They can't be used in place of arbitrary fragments of XPath expression text
(they aren't macros). If $toLang is an element name, then you can find
elements of that name using *[name()=$toLang].
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Dmitri Snytkine [mailto:d(_dot_)snytkine(_at_)gmail(_dot_)com]
Sent: 12 May 2009 12:06
To: xsl-list
Subject: [xsl] Error when params are in Xpath expression
<!-- get translation of a string -->
<xsl:template name="translateString">
<xsl:param name="str" select="'recent_albums'"/>
<xsl:param name="toLang"/>
<xsl:param name="fallback" select="'en'"/>
<xsl:choose>
<xsl:when test="true()">
<xsl:value-of
select="document('')/*/trans:tr/tr_string[(_at_)str=$str]/$toLang"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="'not found'"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
I get errors when running this template.
If I manually replace the $str and $toLang, then I am getting
the correct result.
<xsl:value-of
select="document('')/*/trans:tr/tr_string[(_at_)str='recent_images']/ru"/>
What is wrong with my syntax that uses params? Are params
allowed in Xpath expression?
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