At 2009-05-27 14:28 -0500, Keith Gilbert wrote:
I'm having trouble getting my head around this:
My shortened XML data:
<category>
<category_name>apples</category_name>
<product>red delicious</product>
</category>
<category_name>oranges</category_name>
<product>sunkist</product>
</category>
My simplified XSLT:
<xsl:template match="category">
<xsl:apply=templates/>
</xsl:template>
<xsl:template match="category_name">
<xsl:if test="category_name = apples">
<xsl:call-template name=apple_template/>
</xsl:if>
</xsl:template>
For the life of me I can't figure out how to evaluate the value of
"category_name" in the xsl:if line. I understand (I think) how to use
xsl:value-of, but that doesn't seem to work inside the xsl:if. Any
thoughts?
The content of an element is evaluated as a string from the
concatenation of the descendent text nodes, and you incorrectly have:
<xsl:if test="category_name = apples">
... which tests the content of the child named "category_name" with
the content of the child named "apples".
You want to compare the content to a string:
<xsl:if test="category_name = 'apples'">
I hope this helps.
. . . . . . . Ken
--
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